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x^2+50x+600=5600
We move all terms to the left:
x^2+50x+600-(5600)=0
We add all the numbers together, and all the variables
x^2+50x-5000=0
a = 1; b = 50; c = -5000;
Δ = b2-4ac
Δ = 502-4·1·(-5000)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-150}{2*1}=\frac{-200}{2} =-100 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+150}{2*1}=\frac{100}{2} =50 $
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